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22 June 2016 Left/right asymmetry in reflection and transmission by a planar anisotropic dielectric slab with topologically insulating surface states
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Abstract
The reflection and transmission of plane waves by a homogeneous anisotropic dielectric slab—as represented by a columnar thin film—with topologically insulating surface states was theoretically investigated. Copolarized and cross-polarized reflectances and transmittances were calculated by solving the associated boundary-value problem. Numerical calculations revealed that all four reflectances and all four transmittances were asymmetric with respect to reversal of projection of the propagation direction of the incident plane wave on the illuminated surface of the slab. This left/right reflection and transmission asymmetry arises due to the combined effects of the slab’s anisotropy and surface states.

1.

Introduction

The modest aim of this communication is to theoretically show that a homogeneous anisotropic dielectric slab with topologically insulating surface states (TISS)1,2 reflects and transmits light in such a way as to exhibit asymmetry with respect to reversal of projection of the propagation direction of the incident plane wave on the illuminated surface of the slab. We refer to this phenomenon as left/right asymmetry.

A homogeneous anisotropic material is characterized by a frequency-dependent relative permittivity dyadic ϵ__. Suppose that this material occupies the region Vin bounded by the surface S, which separates Vin from the vacuous region Vout. If the anisotropic material possesses TISS, then the boundary conditions3

Eq. (1)

n^(rS)×[Eout(rS)Ein(rS)]=0n^(rS)×[Hout(rS)Hin(rS)]=γ˜n^(rS)×Ein(rS)},rSS,
hold, with the unit normal vector n^(rS) at rSS pointing into Vout and the admittance γ˜ describing the TISS. Although optical scattering by isotropic dielectric materials, i.e., ϵ__=ϵ(u^xu^x+u^yu^y+u^zu^z), with TISS has been investigated theoretically47 as well as experimentally,2,8 this communication is possibly the first report of optical scattering by an anisotropic dielectric material with TISS. The existence of such materials is deemed possible because the isotropic materials with TISS are chalcogenides,1,2 columnar thin films (CTFs) of other chalcogenides have been fabricated,9 and CTFs function as anisotropic dielectric materials at sufficiently low frequencies.10 Furthermore, periodically multilayered composite materials11,12 comprising laminas of an isotropic topological insulator and some other material should function as effectively anisotropic continuums at sufficiently low frequencies.13

We have found that the TISS induce the exhibition of left/right asymmetry in reflection and transmission by a homogeneous anisotropic dielectric slab. This asymmetry could be exploited for one-way optical devices. The boundary-value problem of reflection and transmission of an obliquely incident plane wave by a homogeneous anisotropic dielectric slab with TISS is described and solved in Sec. 2. Illustrative numerical results are presented and discussed in Sec. 3.

The free-space wavenumber, the free-space wavelength, and the intrinsic impedance of free space are denoted by k0=ωϵ0μ0, λ0=2π/k0, and η0=μ0/ϵ0, respectively, with μ0 and ϵ0 being the permeability and permittivity of free space. We denote the fine structure constant by α˜=(qe2η0)/2h˜, where qe is the quantum of charge and h˜ is the Planck constant. Vectors are in boldface, dyadics are underlined twice, column vectors are in boldface and enclosed within square brackets, while matrixes are underlined twice and similarly bracketed. Cartesian unit vectors are identified as u^x, u^y, and u^z.

2.

Theory

Suppose that the regions Vin={(x,y,z):z(0,L)} and Vout={(x,y,z):z[0,L]} are separated by the surface S={(x,y,z):z{0,L}}.

A plane wave, propagating in the half-space z<0 at an angle θ[0,π/2) to the z-axis and at an angle ψ[0,2π) to the x-axis in the xy plane, is incident on the slab, as shown in Fig. 1. The electromagnetic field phasors associated with the incident plane wave are represented as

Eq. (2)

Einc(r)=(ass+app+)exp[iκ(xcosψ+ysinψ)+ik0zcosθ]Hinc(r)=1η0(asp+aps)exp[iκ(xcosψ+ysinψ)+ik0zcosθ]},z<0.
The amplitudes of the s- and the p-polarized components of the incident plane wave, denoted by as and ap, respectively, are assumed given, whereas

Eq. (3)

κ=k0sinθ,s=u^xsinψ+u^ycosψp±=(u^xcosψ+u^ysinψ)cosθ+u^zsinθ}.

Fig. 1

A plane wave is incident on the slab Vin={(x,y,z):z(0,L)}; the wave vector of the incident plane wave inclined at an angle θ with respect to the z-axis and at an angle ψ with respect to the x-axis in the xy plane. Also shown is the angle χ.

JNP_10_2_020501_f001.png

The reflected electromagnetic field phasors are expressed as

Eq. (4)

Eref(r)=(rss+rpp)exp[iκ(xcosψ+ysinψ)ik0zcosθ]Href(r)=1η0(rsprps)exp[iκ(xcosψ+ysinψ)ik0zcosθ]},z<0,
and the transmitted electromagnetic field phasors as

Eq. (5)

Etr(r)=(tss+tpp+)exp[iκ(xcosψ+ysinψ)+ik0(zL)cosθ]Htr(r)=1η0(tsp+tps)exp[iκ(xcosψ+ysinψ)+ik0(zL)cosθ]},z>L.
The reflection amplitudes rs and rp, as well as the transmission amplitudes ts and tp, have to be determined by the solution of a boundary-value problem.

The frequency-domain electromagnetic constitutive relations of the homogeneous anisotropic dielectric material in Vin can be written as10

Eq. (6)

D(r)=ϵ0ϵ__·E(r),B(r)=μ0H(r),z(0,L),
where the dyadics

Eq. (7)

ϵ__=S__y·(ϵau^zu^z+ϵbu^xu^x+ϵcu^yu^y)·S__yT,

Eq. (8)

S__y=(u^xu^x+u^zu^z)cosχ+(u^zu^xu^xu^z)sinχ+u^yu^y
involve the angle χ[0,π/2]. The superscript T denotes the transpose. The principal relative permittivity scalars ϵa, ϵb, and ϵc, as well as the angle χ, can be chosen for application to either natural crystals14 or the manufactured CTFs.10

In Vin, the electric and magnetic field phasors can be represented as15

Eq. (9)

E(r)=e(z)exp[iκ(xcosψ+ysinψ)]H(r)=h(z)exp[iκ(xcosψ+ysinψ)]},
where the vector functions e(z) and h(z) are unknown. Substitution of Eqs. (6) and (9) in the Maxwell curl postulates followed by certain algebraic manipulations leads to the 4×4-matrix ordinary differential equations

Eq. (10)

ddz[f(z)]=i[P__]·[f(z)],zVin,
where the column vector

Eq. (11)

[f(z)]=[ex(z),ey(z),hx(z),hy(z)]T,
the 4×4 matrix

Eq. (12)

[P__]=ω[000μ000μ000ϵ0ϵc00ϵ0ϵd000]+κϵd(ϵaϵb)2ϵaϵbsin(2χ)[cosψ000sinψ000000000sinψcosψ]+κ2ωϵ0ϵdϵaϵb[00cosψsinψcos2ψ00sin2ψcosψsinψ00000000]+κ2ωμ0[00000000cosψsinψcos2ψ00sin2ψcosψsinψ00],
and the scalar

Eq. (13)

ϵd=ϵaϵbϵacos2χ+ϵbsin2χ.

Equation (10) has the following straightforward solution:

Eq. (14)

[f(L)]=exp{i[P__]L}·[f(0+)],
where the notation [f(a±)] stands for limδ0[f(a±δ)] with δ0. Application of the boundary conditions [Eq. (1)] to the planes z=0 and z=L leads to

Eq. (15)

[f(0)]=[V__]·[f(0+)],

Eq. (16)

[f(L+)]=[V__]·[f(L)],
respectively, where the matrix

Eq. (17)

[V__]=[10000100γ˜0100γ˜01].
Combining Eqs. (14)–(16), we get

Eq. (18)

[f(L+)]=[V__]·exp{i[P__]L}·[V__]1·[f(0)].

But the elements of [f(0)] are known by virtue of Eqs. (2) and (4), and those of [f(L+)] by virtue of Eq. (5). Accordingly, Eq. (18) may be written as

Eq. (19)

[tstp00]=[K__]1·[V__]·exp{i[P__]L}·[V__]1·[K__]·[asaprsrp],
where

Eq. (20)

[K__]=[sinψcosψcosθsinψcosψcosθcosψsinψcosθcosψsinψcosθ(1η0)cosψcosθ(1η0)sinψ(1η0)cosψcosθ(1η0)sinψ(1η0)sinψcosθ(1η0)cosψ(1η0)sinψcosθ(1η0)cosψ].

The solution of Eq. (19) yields the reflection and transmission coefficients that appear as the elements of the 2×2 matrixes in the following relations:

Eq. (21)

[rsrp]=[rssrsprpsrpp][asap],[tstp]=[tsstsptpstpp][asap].
Copolarized coefficients have both subscripts identical, but cross-polarized coefficients do not. The square of the magnitude of a reflection or transmission coefficient is the corresponding reflectance or transmittance; thus, Rsp=|rsp|2 is the reflectance corresponding to the reflection coefficient rsp, and so on. The principle of conservation of energy mandates the constraints Rss+Rps+Tss+Tps1 and Rpp+Rsp+Tpp+Tsp1. Let us note here that a real-valued γ˜ does not cause dissipation.

3.

Numerical Results and Discussion

Let the left side of the xy plane be specified by ψ[0,π] and the right side by ψ[π,2π]. In order to delineate the characteristics of and the factors responsible for left/right asymmetry of reflection and transmission, we need to consider four distinct cases as follows.

Case I: Suppose that ϵa=ϵb=ϵc and γ˜=0. Then the material in Vin is a homogeneous isotropic dielectric material and the TISS are absent. The boundary-value problem then turns into a textbook reflection/transmission problem.16 None of the four reflectances (Rss, Rps, Rpp, and Rss) and the four transmittances (Tss, Tps, Tpp, and Tss) then depend on ψ. Furthermore, the cross-polarized remittances are null valued. In other words, the following relationships hold:

Eq. (22)

Rss(θ,ψ)=Rss(θ,0),Rpp(θ,ψ)=Rpp(θ,0)Tss(θ,ψ)=Tss(θ,0),Tpp(θ,ψ)=Tpp(θ,0)Rps(θ,ψ)=Rsp(θ,ψ)0,Tps(θ,ψ)=Tsp(θ,ψ)0}.
In particular, all reflectances and transmittances are unchanged upon replacing ψ with ψ+π; i.e., all are left/right symmetric.

Case II: Suppose next that ϵa=ϵb=ϵc but γ˜0. Then the material in Vin is a homogeneous isotropic dielectric material with TISS. None of the eight remittances (Rss, and so on, and Tss, and so on) then depend on ψ, and the cross-polarized remittances are not identically zero. Analysis of numerical results reveals that the following relationships hold:

Eq. (23)

Rss(θ,ψ)=Rss(θ,0),Rpp(θ,ψ)=Rpp(θ,0)Tss(θ,ψ)=Tss(θ,0),Tpp(θ,ψ)=Tpp(θ,0)Rps(θ,ψ)=Rsp(θ,ψ)0,Tps(θ,ψ)=Tsp(θ,ψ)0}.
A comparison of Eqs. (22) and (23) indicates that the TISS are responsible for de-polarization on both reflection and transmission. As in case I, all eight remittances are left/right symmetric.

Case III: Suppose that ϵa, ϵb, and ϵc are all dissimilar, but γ˜=0. Then the material in Vin is a homogeneous anisotropic dielectric material and the TISS are absent. Calculations then show the following symmetries:

Eq. (24)

Rss(θ,ψ)=Rss(θ,ψ+π),Rpp(θ,ψ)=Rpp(θ,ψ+π)Rps(θ,ψ)=Rsp(θ,ψ+π)0,Tps(θ,ψ)=Tsp(θ,ψ)0}.
While both Rss and Rpp are left/right symmetric, both Tss and Tpp are not. Furthermore, as Rps(θ,ψ)Rsp(θ,ψ) and Tps(θ,ψ)Tsp(θ,ψ+π), it follows that all cross-polarized remittances are left/right asymmetric. In summary, the following inequalities are entirely due to anisotropy:

Eq. (25)

Rps(θ,ψ)Rps(θ,ψ+π),Rsp(θ,ψ)Rsp(θ,ψ+π)Tss(θ,ψ)Tss(θ,ψ+π),Tpp(θ,ψ)Tpp(θ,ψ+π)Tps(θ,ψ)Tps(θ,ψ+π),Tsp(θ,ψ)Tsp(θ,ψ+π)}.

Case IV: Finally, ϵa, ϵb, and ϵc are all dissimilar and γ˜0, so that the material in Vin is a homogeneous anisotropic dielectric material with TISS. All eight remittances then depend on ψ, the cross-polarized remittances are not identically zero, and only one relationship can be found.

Eq. (26)

Tps(θ,ψ)=Tsp(θ,ψ)0.
All eight remittances exhibit left/right asymmetry, i.e.,

Eq. (27)

Rss(θ,ψ)Rss(θ,ψ+π),Rpp(θ,ψ)Rpp(θ,ψ+π)Rps(θ,ψ)Rps(θ,ψ+π),Rsp(θ,ψ)Rsp(θ,ψ+π)Tss(θ,ψ)Tss(θ,ψ+π),Tpp(θ,ψ)Tpp(θ,ψ+π)Tps(θ,ψ)Tps(θ,ψ+π),Tsp(θ,ψ)Tsp(θ,ψ+π)}.
Furthermore, by comparison with cases I to III, we deduce that these inequalities arise due to the combined effects of the slab’s anisotropy and the presence of TISS. Without anisotropy, cases I and II show that the TISS are responsible for the cross-polarized reflectances and transmittances, but do not give rise to left/right asymmetry. Without TISS, case III shows that only the two copolarized transmittances (out of the eight remittances) are left/right asymmetric when the slab is made of an anisotropic material.

The complete left/right asymmetry that arises for case IV is illustrated in Figs. 2 and 3, wherein all reflectances and transmittances, respectively, are plotted as functions of the incidence angles θ[0,π/2) and ψ[0,2π). For these representative calculations, we chose ϵa=2.14, ϵb=3.67, ϵc=2.83, χ=38  deg, γ˜=100α˜/η0, and L=1.4λ0. The chosen values of ϵa,b,c emerged from a homogenization model for dielectric CTFs,15 whereas γ˜1719 was chosen to clearly highlight left/right asymmetry, in the absence of any experimental data for anisotropic topological insulators.

Fig. 2

Reflectances Rss, Rps, Rpp, and Rsp as functions of the incidence angles θ[0,π/2) and ψ[0,2π) when ϵa=2.14, ϵb=3.67, ϵc=2.83, χ=38  deg, γ˜=100α˜/η0, and L=1.4λ0. The color coding employs the spectrum of the rainbow with the deepest violet denoting 0 and the deepest red denoting 1.0.

JNP_10_2_020501_f002.png

Fig. 3

Same as Fig. 2, except that the transmittances Tss, Tps, Tpp, and Tsp are displayed as functions of θ and ψ.

JNP_10_2_020501_f003.png

The inequalities in Eq. (27) are readily observed in the two figures. The left/right asymmetry is most easily discernible in the plots of Rss (Fig. 2) and Tpp (Fig. 3), but can be identified in the plots of the remaining six remittances too for mid-range values of θ.

In further numerical calculations (not presented here), the left/right asymmetry was found to be even more conspicuous for various remittances, when the magnitude of γ˜ was increased. Intrinsic topological insulators are characterized by γ˜=±α˜/η0,1 but a very thin coating of a magnetic material can be used to realize γ˜=(2q+1)α˜/η0, q{0,±1,±2,±3,}.17,18 Values of q other than 1 and 0 can also be obtained by immersing a topological insulator in a magnetostatic field.19

Practically oriented research on topological insulators is embryonic though steady progress is being made in the identification of several relevant materials.2,20 As stated in Sec. 1, attention is chiefly being given to isotropic topological insulators, although the fabrication of anisotropic topological insulators appears possible. The exploitation of left/right asymmetry theoretically shown here to be possible with anisotropic topological insulators is promising for one-way optical devices, which could reduce backscattering noise21 in optical communication networks, microscopy, and tomography, for example. But high magnitudes of η0γ˜/α˜ would be needed for practical implementation.

Acknowledgments

A.L. is grateful to the Charles Godfrey Binder Endowment at Penn State for the ongoing support of his research. T.G.M. acknowledges the support of EPSRC Grant EP/M018075/1.

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Biography

Akhlesh Lakhtakia received degrees from the Banaras Hindu University and the University of Utah. He is the Charles Godfrey Binder Professor of Engineering Science and Mechanics at the Pennsylvania State University. His research interests include surface multiplasmonics, biorepli-cation, forensic science, solar energy, sculptured thin films, and mimumes. He is a fellow of OSA, SPIE, IoP, AAAS, APS, and IEEE. He received the 2010 SPIE Technical Achievement Award and the 2016 Walston Chubb Award for Innovation.

Tom G. Mackay is a reader in the School of Mathematics at the University of Edinburgh and an adjunct professor in the Department of Engineering Science and Mechanics at the Pennsylvania State University. He is a graduate of the Universities of Edinburgh, Glasgow, and Strathclyde, and a fellow of the Institute of Physics (UK) and SPIE. His research interests include the electromagnetic theory of novel and complex materials, including homogenized composite materials.

CC BY: © The Authors. Published by SPIE under a Creative Commons Attribution 4.0 Unported License. Distribution or reproduction of this work in whole or in part requires full attribution of the original publication, including its DOI.
Akhlesh Lakhtakia and Tom G. Mackay "Left/right asymmetry in reflection and transmission by a planar anisotropic dielectric slab with topologically insulating surface states," Journal of Nanophotonics 10(2), 020501 (22 June 2016). https://doi.org/10.1117/1.JNP.10.020501
Published: 22 June 2016
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CITATIONS
Cited by 9 scholarly publications.
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KEYWORDS
Dielectrics

Picosecond phenomena

Reflection

Anisotropy

Contrast transfer function

Electromagnetism

Thin films

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